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# Circuit Theory Lecturer

Texas, USA

## Simon M

Doctor of Philosophy, Electrical Engineering, University of Houston, USA

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Full time online electrical engineering tutor

Skills

I have been teaching electrical engineering for close to ten years now to college and university students. Before 2016 I worked full-time as a lecturer at a local university but during my free time, I would offer online tuition as an independent freelancer. But the more I did freelancing, the more I loved working remotely and so I decided to apply for a tutoring position at Matlab Assignment Experts. Since then, I have been administering online lessons on various electrical engineering topics such as circuit theory, electrical installations, microprocessors, electrical control systems, and power engineering, to name a few. If you are looking for convenient and pocket-friendly tutoring services on any of these topics, then I am the person for the job.

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%% Question 2 % Input values vxi = [0 -0.2478 -0.4943 -0.7384 -0.9786]; vyi = [4 3.9915 3.9659 3.9234 3.8644]; ti = [0 0.04 0.08 0.12 0.17]; % Initial values x1 = 4; y1 = 0; % Calculate x2, x3, x4, y2, y3, y4 x2 = x1 + vxi(1)*(ti(2)-ti(1)); x3 = x1 + vxi(2)*(ti(3)-ti(2)); x4 = x1 + vxi(3)*(ti(4)-ti(3)); y2 = y1 + vyi(1)*(ti(2)-ti(1)); y3 = y1 + vyi(2)*(ti(3)-ti(2)); y4 = y1 + vyi(3)*(ti(4)-ti(3)); %% Question 3 % Read file into a table data = readtable('A1_input.txt'); % Do not take into account the first element of the data because that one % contains the units for k = 2:size(data,1) t(k-1) = str2double(data.time{k}); vx(k-1) = str2double(data.vx{k}); vy(k-1) = str2double(data.vy{k}); end % Display the first four values [t(1:4)', vx(1:4)', vy(1:4)'] %% Question 4 % Plot vx and vy in the same graph figure plot(t, vx, t, vy); grid on legend('vx', 'vy'); xlabel('Time (s)'); ylabel('Velocity (m/s)'); grid on %% Question 5 % Calculate x and y positions using for loop x(1) = x1; y(1) = y1; for k = 2:length(t) x(k) = x1; y(k) = y1; for j = 1:k-1 x(k) = x(k) + vx(j)*(t(j+1)-t(j)); y(k) = y(k) + vy(j)*(t(j+1)-t(j)); end end %% Question 6 % Calculate x and y positions with vector operations % x and y using vectors % vectors of tj+1 tj tvec = t(2:end) - t(1:end-1); xv = cumsum(vx(1:end-1).*tvec); xv = xv + x1; xv = [x1, xv]; yv = cumsum(vy(1:end-1).*tvec); yv = yv + y1; yv = [y1, yv]; %% Question 7 % Plot the original datapoints and the calculated ones figure hold on plot(t, x); plot(t, y); plot(t, xv, 'k--', 'linewidth', 3); plot(t, yv, 'g--', 'linewidth', 3); grid on xlabel('Time (s)'); ylabel('Position'); legend('X-position from Q5', 'Y-position from Q5', 'X-position from Q6', 'Y-position from Q6'); %% Question 8 % Plot the trajectory figure plot(xv, yv), grid on xlabel('X-Position (m)'); ylabel('Y-Position (m)'); %% Question 9 % Write a new file file = fopen('output.txt', 'wt'); fprintf(file, 'Time\tx\ty\n'); fprintf(file, '(s)\t(m)\t(m)\n'); for k = 1:length(t) fprintf(file, '%.3f\t%.3f\t%.3f\n', t(k),xv(k), yv(k)); end fclose(file); %% Question 10 % Write a new file file = fopen('output2.txt', 'wt'); fprintf(file, 'Time\tx\ty\n'); fprintf(file, '(s)\t(m)\t(m)\n'); fprintf(file, '%.3f\t%.3f\t%.3f\n', t',xv', yv'); fclose(file); 
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P = 0; % initial money in the account deposit_per_year = [288, 345, 355, 382, 392]; % amounts deposited each month, per year (year 1, year2, ... year5) withdraw = 2331; % amount to be withdrawn each year r = 0.04; % interes of the saving account rcd = 0.08; % interest of the CD n_CD = 0; % number of CDs bought year = 1; deposited = 0; for i = 1:5*12 % 5 years, 12 months per year: total 60 months % if i < 60 % deposited = deposit_per_year(year); % else % deposited = deposit_per_year(5); % end deposited = deposit_per_year(year); P = P*(1+r); P = P + deposited; fprintf("Deposited %.2f at month %.0f. Current amount: %.4f\n", deposited, i, P); if mod(i,12) == 0 % the end of a year if P > 2811 fprintf('Amount in account: %.4f. Withdrawed %.2f at the end of year %0.f\n', P, withdraw, year); P = P - withdraw; n_CD = n_CD + 1; % Formula of compound anually. We use the interest rate of the % CD multiplied by the number of CDs P = P*(1+(n_CD-1)*rcd); end year = year + 1; end end fprintf("\nThe final amount in the account after %.0f years is: %.4f\n", 5, P)